# How do you write y=3/8x-3/4 in standard form?

Jun 28, 2015

$y = \frac{3}{8} x - \frac{3}{4}$ in standard form is $3 x - 8 y = 6$.

#### Explanation:

Standard form for a linear equation is $A x + B y = C$.

$y = \frac{3}{8} x - \frac{3}{4}$

Simplify $\frac{3}{8} x$ to $\frac{3 x}{8}$.

Subtract $\frac{3 x}{8}$ from both sides of the equation.

$\frac{- 3 x}{8} + y = - \frac{3}{4}$

Multiply both sides by $- 1$.

$\frac{- 3 x}{8} \left(- 1\right) + y \left(- 1\right) = - \frac{3}{4} \left(- 1\right)$ =

$\frac{3 x}{8} - y = \frac{3}{4}$

Multiply both sides by $8$.

$\frac{\left(3 x\right) \cdot 8}{8} - y \left(8\right) = \frac{\left(3\right) \cdot 8}{4}$ =

$\frac{\left(3 x\right) \cdot {\cancel{8}}^{1}}{{\cancel{8}}^{1}} - y \left(8\right) = \frac{\left(3\right) \cdot {\cancel{8}}^{2}}{{\cancel{4}}^{1}}$ =

$3 x - 8 y = 6$