How do you write #y+4=2/3(x+7)# in standard form?

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Answer 1 · 2017-01-31T12:59:21

#2x-3y = -2#

A linear equation with an #x, y# and number term represents a straight line.
It can be written in different forms:

General form: #ax +by +c =0" "larr# no fractions

Standard form: #ax +by = c" "larr# no fractions

Slope/intercept form: #y = mx +c" "larr# may have fractions

#y+4 = 2/3(x+7)" "larr" "xx 3# to get rid of the denominator

#3y +12 = 2(x+7)" "larr# multiply the bracket by 2

#3y +12 = 2x+14" "larr# re-arrange the terms

The #x# term is usually positive

#12-14 = 2x-3y#

#2x-3y = -2#