# How do you write y = 4(x - 2)^2 - 1 in standard form?

Feb 28, 2017

$y = 4 {x}^{2} - 16 x + 15$

#### Explanation:

Standard form is as follows:
$y = a {x}^{2} + b x + c$

1. $y = 4 {\left(x - 2\right)}^{2} - 1$
2. $y = 4 \left(x - 2\right) \left(x - 2\right) - 1$
3. $y = 4 \left({x}^{2} - 4 x + 4\right) - 1$
4. $y = 4 {x}^{2} - 16 x + 16 - 1$
5. $y = 4 {x}^{2} - 16 x + 15$