How do you write $y = (4 x + 1) (2 x - 3)$ $y = (4x + 1)(2x − 3)$ in standard form?

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Answer 1 · 2015-09-17T17:16:51

$y = 8 {(x - \frac{5}{8})}^{2} - \frac{49}{8}$ $y= 8(x-5/8)^2 -49/8$

It is $y = 8 x^{2} - 10 x - 3$ $y= 8x^2-10x-3$

$= 8 (x^{2} - \frac{5 x}{4}) - 3$ $=8(x^2 -(5x)/4)-3$

$= 8 (x^{2} - \frac{5 x}{4} + \frac{25}{64} - \frac{25}{64}) - 3$ $= 8 (x^2 -(5x)/4 +25/64-25/64) -3$

$= 8 {(x - \frac{5}{8})}^{2} - 3 - \frac{25}{8}$ $= 8 (x-5/8)^2 -3-25/8$

$= 8 {(x - \frac{5}{8})}^{2} - \frac{49}{8}$ $= 8(x-5/8)^2 -49/8$

How do you write y=(4x+1)(2x−3)y = (4x + 1)(2x − 3) in standard form?