How do you write y + 9 = -3(x - 2)  in standard form?

Jan 23, 2017

$3 x + y + 3 = 0$

Explanation:

The equation of a line in $\textcolor{b l u e}{\text{standard form}}$ is.

$\textcolor{red}{\overline{\underline{| \textcolor{w h i t e}{\frac{2}{2}} \textcolor{b l a c k}{a x + b y + c = 0} \textcolor{w h i t e}{\frac{2}{2}} |}}}$

Rearrange $y + 9 = - 3 \left(x - 2\right) \text{ into this form}$

distribute the bracket.

$y + 9 = - 3 x + 6$

add 3x to both sides.

$y + 3 x + 9 = \cancel{- 3 x} \cancel{+ 3 x} + 6$

$\Rightarrow y + 3 x + 9 = 6$

subtract 6 from both sides.

$y + 3 x + 9 - 6 = \cancel{6} \cancel{- 6}$

$\Rightarrow 3 x + y + 3 = 0 \leftarrow \textcolor{red}{\text{ in standard form}}$