# How does concentration effect an electrochemical cell?

Nov 9, 2017

Let's consider a Zn-Cu cell:

$Z n \left(s\right) + C {u}^{2 +} r i g h t \le f t h a r p \infty n s Z {n}^{2 +} + C u \left(s\right)$

This is in dynamic equilibrium.

If I increase the concentration of $C {u}^{2 +}$, ceteris paribus, the electrical potential of the cell will increase, due to the $Q$ value increasing.

I like to think of this equation, but Le Chatlier's principle may be useful as well:

$E = {E}^{0} - \frac{0.05916}{n} \cdot \log Q$

If I decrease the concentration of cathode ions, the voltage will decrease.

Hence,

$E \propto \frac{\left[{I}_{a n o \mathrm{de}}\right]}{\left[{I}_{c a t h o \mathrm{de}}\right]}$

If I'm wrong correct me!