# How does the (R)/(S) method work to convert Fischer projections to bond line views?

Jan 29, 2015

A bond-line view gives no stereochemical information. I presume that you want to convert a Fischer projection to a wedge-dash view using ($R \text{/} S$) information.

Step 2. Convert this to a "bow tie" view by making all the horizontal bonds into wedges.

Step 3. Assign configurations to the chiral carbons.

The assignments are $\left(2 R , 3 S , 4 R , 5 R\right)$.

Glucose is $\left(2 R , 3 S , 4 R , 5 R\right)$-2,3,4,5,6-pentahydroxyhexanal.

Step 4. Draw the wedge-dash structure.

Draw a trial zig-zag structure. Arbitrarily make all the H bonds wedges and the OH bonds dashes.

Some of them will be correct. Others won't.

Assign configurations to the chiral carbons.

The assignments are $\left(2 R , 3 S , 4 R , 5 S\right)$. Oops! Number 5 is wrong. We must interchange the wedge and dash.

We get

This is the wedge-dash structure of glucose.

Step 6. (If you really wanted this) Convert to a bond-line structure.

Omit the H atoms on the chain and convert the wedges and dashes to solid lines.

This structure could represent any of the 16 aldohexoses.