How does this simpify?

My book says #(10/(11+h)-10/11)/h# simplifies to #(-(10h)/(11h+121))/h#

But I just can't figure out how they came to that conclusion.

2 Answers
Sep 3, 2016

How do you get the second equation from the first?

Explanation:

I don't understand how to book gets to #(-(10h)/(11h+121))/h# from the original equation. Why does the numerator of the top of the equation become 10h? Why are both denominators being multiplied by 11 in order to get 11h and 121?

Sep 3, 2016

#-10/((11+h)11)#

Explanation:

#(10/(11 + h) - 10/11)/h = ((10 xx 11-10(11+h))/((11+h)11))/h=((10 xx 11-10 xx 11-10h)/((11+h)11))/h=-10/((11+h)11)#