# How fast will an object with a mass of 15 kg accelerate if a force of 40 N is constantly applied to it?

Feb 13, 2017

The acceleration of the object is $2.67 \frac{m}{s} ^ 2$ [forward].

#### Explanation:

Before we solve this question, we have to assume something.

1. The force of friction, ${F}_{\text{F}}$, will be ignored.

2. No direction is specified, however, a force is applied to the object. The movement produced will be referred to as motion in a positive direction.

The formula we are using is: ${F}_{\text{NET}} = m a$
=> where ${F}_{\text{NET}}$ is the net force in $N$, $m$ is the mass in $k g$, and $a$ is the acceleration in $\frac{m}{s} ^ 2$.

If we ignore friction, the only force is the applied force, ${F}_{\text{A}}$. Thus ${F}_{\text{NET" = F_"A}}$.

We can rearrange the equation ${F}_{\text{NET}} = m a$, to get $a$
=> $a = {F}_{\text{NET}} / m$

$a = {F}_{\text{NET}} / m$

$= \frac{40}{15}$

$= 2.67$

Therefore, the acceleration of the object is $2.67 \frac{m}{s} ^ 2$ [forward].

Hope this helps :)