# How fast will an object with a mass of 8 kg accelerate if a force of 63 N is constantly applied to it?

Nov 6, 2017

$7.875 m {s}^{- 2}$

#### Explanation:

Using Newton's second Law

$F = m a$

$F = 63 N$the force applied

$m = 8 k g$the mass

$a =$acceleration

in this case

63=8a#

$\therefore a = \frac{63}{8} = 7.875 m {s}^{- 2}$

Nov 6, 2017

With my chosen interpretation of the question, the acceleration is $7.9 \frac{m}{s} ^ 2$.

#### Explanation:

If the net force on this object is 63 N, it is a simple application of ${F}_{\text{net}} = m \cdot a$. But, is that 63 N one of 2 or more forces on this object?

It could be that the direction of this force is directly up and that the 8 kg object is in on Earth where $g = - 9.8 \frac{m}{s} ^ 2$. In that situation, we would find that the object is heavier than 63 N and it would therefore accelerate downwards more slowly than in free-fall.

But I will choose the simplest interpretation of your question: the 63 N force is applied horizontally and there is no friction.

${F}_{\text{net}} = m \cdot a$.

$63 N = 8 k g \cdot a$

$a = \frac{63 N}{8 k g} = 7.9 \frac{N}{k g} = 7.9 \frac{m}{s} ^ 2$

I hope this helps,
Steve