How I can predict the group and from following configuration? 6s2, 5d1, 4f3 .
2 Answers
Nov 21, 2017
See the answer below....
Explanation:
There is a rule to predict the group and period of an element by its ELECTRONIC CONFIGURATION...
For S Block elements:-
- Last electronic configuration:-
#color(red)(n"S"^(1-2)# where#n=1,2,3...# - Group of the element:-
#(color(green)(1-2))# for#S^1# is#1# and for#S^2# is#2# .- Period:-the value of
#color(red)(n# For P Block elements:-
- Last electronic configuration:-
#color(red)(n"S"^2n"P"^(1-6))# where#n=1,2,3...# - Group of the element:- 1) for
#color(red)(n=1# , group is#color(red)(13#
#color(white)(QQQQQQQQQQQhhhhhhdQ# 2) for#color(red)(n=2# , group is#color(red)(14#
#color(white)(QQQQQQQQQQQhhhhhhdQ# 3) for#color(red)(n=3# , group is#color(red)(15#
#color(white)(QQQQQQQQQQQhhhhhhdQ# 4) for#color(red)(n=4# , group is#color(red)(16#
#color(white)(QQQQQQQQQQQhhhhhhdQ# 5) for#color(red)(n=5# , group is#color(red)(17#
#color(white)(QQQQQQQQQQQhhhhhhdQ# 6) for#color(red)(n=6# , group is#color(red)(18# - Period:-the value of
#color(red)(n# For D Block elements:-
- Last electronic configuration:-
#color(red)((n-1)"D"^(1-10)n"S"^(2 or, 1# where#n=1,2,3...# - Group of the element:-
#color(white)(QQQQQQQQQQQhhhhhdQ# 1) for#color(red)(n=1# , group is#color(red)3#
#color(white)(QQQQQQQQQQQhhhhhdQ# 2) for#color(red)(n=2# , group is#color(red)(4#
#color(white)(QQQQQQQQQQQhhhhhdQ# 3) for#color(red)(n=3# , group is#color(red)(5#
#color(white)(QQQQQQQQQQQhhhhhdQ# 4) for#color(red)(n=4# , group is#color(red)(6#
#color(white)(QQQQQQQQQQQhhhhhdQ# 5) for#color(red)(n=5# , group is#color(red)(7#
#color(white)(QQQQQQQQQQQhhhhhdQ# 6) for#color(red)(n=6# , group is#color(red)(8#
#color(white)(QQQQQQQQQQQhhhhhdQ# 7) for#color(red)(n=7# , group is#color(red)(9#
#color(white)(QQQQQQQQQQQhhhhhdQ# 8) for#color(red)(n=8# , group is#color(red)(10#
#color(white)(QQQQQQQQQQQhhhhhdQ# 9) for#color(red)(n=9# , group is#color(red)(11#
#color(white)(QQQQQQQQQQQhhhhhdQ# 10) for#color(red)(n=10# , group is#color(red)(12# - Period:-the value of
#color(red)(n# For F Block elements:-
- Last electronic configuration:-
#color(red)((n-2)"F"^(1-14)(n-1)"D"^(0-1)n"S"^2# where#n=1,2,3...# - Group of the element:- always
#color(red)(3# because these elements are inner transitional elements...- Period of the element:- the value of
#color(red)(n# Hope it helps...
Thank you...
Nov 21, 2017
See the rules I have written...
Let's answer...
Explanation:
#6"S"^2 5"D"^1" 4F"^3# is an#F# block element which has a electronic configuration of#F# block element. It is of#color(red)(3# no. group..Hope it helps...
Thank you...