How is impulse related to momentum?

1 Answer
Jun 11, 2018

Answer:

#underbrace(bbJ = int_(t_1)^(t_2) bbF \ dt)_("Impulse") = underbrace(bb p_2 -bb p_2)_("Change in Momentum")#

Explanation:

Newton's 2nd Law:

  • #bbF = dot bb p#

#implies underbrace(Delta bb p = dot bb p Delta t)_("Change in Momentum") = underbrace(bb F Delta t)\_("Impulse")#

In integral form:

#underbrace(bbJ = int_(t_1)^(t_2) bbF \ dt)_("Impulse") = underbrace(bb p_2 - bb p_2)_("Change in Momentum")#