# How many atoms are represented in 5.78 moles of C_6H_12O_6 glucose?

Jul 17, 2017

Approx. $5.8 \times {N}_{A} \times 24$

#### Explanation:

${N}_{A}$ specifies $\text{Avogadro's number}$ $\equiv$ $6.022 \times {10}^{23} \cdot m o {l}^{-} 1$. And $\text{the mole}$ this is simply another collective number like a dozen, or a score, or a gross........

And we gots $5.78 \cdot m o l$ of glucose.......

And thus the number of atoms is........

$5.78 \times \left\{{6}_{\text{carbon atoms"+12_"hydrogen atoms"+6_"oxygen atoms}}\right\} \times {N}_{A}$

$138.72 \times {N}_{A}$ atoms in total........

Can you tell me the mass of this number of atoms? This is the next question you will be asked.