How many calories are absorbed by a pot of water with a mass of 500 g in order to raise the temperature from 20° C to 30° C?

1 Answer
Jan 15, 2016

Answer:

The water absorbs 5000 cal.

Explanation:

I assume that the pot itself absorbs no heat.

The formula for the heat absorbed by the water is

#q = mcΔt#, where

#m = "500 g"#
#c = 1.00color(white)(l) "cal°C"^(-1)"g"^(-1)#
#ΔT = T_2 –T_1 = "30 °C – 20°C" = "10 °C"#

#q = mcΔT = 500 color(red)(cancel(color(black)("g"))) ×1.00color(white)(l) "cal"color(red)(cancel(color(black)("°C"^(-1)"g"^(-1)))) × 10 color(red)(cancel(color(black)("°C"))) = "5000 cal"#