How many grams of CaCl2 would you use to make 500 ml of a 6mM calcium salt solution? CaCl2=110

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Feb 25, 2018

Answer:

#0.33g#

Explanation:

Since #n=cV#,

#n(CaCl_2) = 0.5 dm^3*0.006M = 3xx10^-3 mol#

Finally, since #M=nMr#,

#M(CaCl_2) = 3xx10^-3 mol*110gmol^-1 = 0.33g#

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