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# How many grams of CaCl2 would you use to make 500 ml of a 6mM calcium salt solution? CaCl2=110

Feb 25, 2018

$0.33 g$

#### Explanation:

Since $n = c V$,

$n \left(C a C {l}_{2}\right) = 0.5 {\mathrm{dm}}^{3} \cdot 0.006 M = 3 \times {10}^{-} 3 m o l$

Finally, since $M = n M r$,

$M \left(C a C {l}_{2}\right) = 3 \times {10}^{-} 3 m o l \cdot 110 g m o {l}^{-} 1 = 0.33 g$