How many grams of #CaO# can be formed from the decomposition of 275 g of #CaCO_3#?

1 Answer
Jan 7, 2017

Answer:

Approx. #150*g# #"calcium oxide"# will be isolated given stoichiometric reaction.

Explanation:

We need (i) a stoichiometric equation:

#CaCO_3(s) + Delta rarr CaO(s) + CO_2(g)#

And (ii) equivalent quantities of #"calcium carbonate"#,

#"Moles of calcium carbonate"=(275*g)/(100.09*g*mol^-1)=2.75*mol#

And thus #2.75*molxx56.08*g*mol^-1=??*g# #"calcium oxide"#.

Why is there #"1:1"# equivalence between #"calcium oxide"# and #"calcium carbonate"#.