How many grams of #CH_4# are present in #5.14*10^23# molecules of #CH_4#?

1 Answer
Aug 15, 2016

Answer:

Well, #6.022xx10^23# methane molecules have a mass of #16.01*g#.

Explanation:

So,

#(5.14xx10^23*"methane molecules")/(6.022xx10^23*"methane molecules mol"^-1)xx16.01*g*mol^-1#

#~=# #13*g#