# How many grams of fluorine gas will exert a pressure of 1.54 atm in a 3.2-liter container at 40 °C?

May 8, 2017

You MUST know that elemental fluorine is the gaseous ${F}_{2}$ molecule.

#### Explanation:

And in fact all the elemental gases, save for the Noble Gases, are bimolecular species. Is this true?

And we use the Ideal Gas Equation:

$P V = n R T = \text{mass"/"molar mass} \times R T$

And thus "mass"=(PVxx"molar mass")/(RT)

And we plugs in the numbers:

$\frac{1.54 \cdot a t m \times 3.2 \cdot L \times 38.0 \cdot g \cdot m o {l}^{-} 1}{0.0821 \cdot \frac{L \cdot a t m}{K \cdot m o l} \times 313.1 \cdot K} =$

$7.29 \cdot g$.

Remember what I said with regard to the so-called molecularity of elemental gases. And fluorine gas, the most reactive substance on the Periodic Table, is not to be handled without special precautions.