Question

How many grams of oxygen gas present in a 2.50-L sample kept at 1.66 atm pressure and a temperature of 10.0°C?

Answer 1

Approx. `0.2*mol`

Explanation:

We use the Ideal Gas equation: `PV=nRT`, and the appropriate gas constant `R`.

`n` `=` `(PV)/(RT)` `=` `(1.66*atmxx2.50*L)/(0.0821*L*atm*K^-1*mol^-1xx283*K)`

`~=` `0.20*mol`