How many joules are required for heating 65 g of water from 12 °C to 76 °C?

1 Answer
Mar 16, 2017

Answer:

#17000# joules

Explanation:

With knowledge of the specific heat capacity of a substance, its mass, and the temperature change, we can convert this to the energy required for this temperature change using:

#DeltaH=mCDeltaT#, where

#DeltaH=#change in enthalpy (J)

#m=# mass of substance being heated (g) i.e. water in this question

#C=# specific heat capacity (J/g°C)

#DeltaT=# change in temperature (°C)

We know mass#=65g# and #DeltaT=76°C-12°C=64°C#

The specific heat capacity of water is #4.18#J/g°C

Therefore, #DeltaH=65cancel(g)*(4.18J)/cancel(g°C)*64cancel(°C)#

#=17388.8J#

#=17000J# (2 significant figures)