# How many joules are required for heating 65 g of water from 12 °C to 76 °C?

Mar 16, 2017

$17000$ joules

#### Explanation:

With knowledge of the specific heat capacity of a substance, its mass, and the temperature change, we can convert this to the energy required for this temperature change using:

$\Delta H = m C \Delta T$, where

$\Delta H =$change in enthalpy (J)

$m =$ mass of substance being heated (g) i.e. water in this question

$C =$ specific heat capacity (J/g°C)

$\Delta T =$ change in temperature (°C)

We know mass$= 65 g$ and DeltaT=76°C-12°C=64°C

The specific heat capacity of water is $4.18$J/g°C

Therefore, DeltaH=65cancel(g)*(4.18J)/cancel(g°C)*64cancel(°C)

$= 17388.8 J$

$= 17000 J$ (2 significant figures)