# How many joules of heat energy would be required to raise the temperature of 150.0 g of aluminum from 23°C to 150°C?

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The specific heat capacity of aluminum is .90 #J# #/g*°C# .

The specific heat capacity of aluminum is .90

##### 1 Answer

#### Explanation:

Your tool of choice here will be the following equation

#color(blue)(|bar(ul(color(white)(a/a)q = m * c * DeltaTcolor(white)(a/a)|)))" "# , where

*change in temperature*, defined as the difference between the **final temperature** and the **initial temperature**

The problem provides you with all the information that you need in order to determine the amount of heat,

In your case, the change in temperature will be

#DeltaT = 150^@"C" - 23^@"C" = 127^@"C"#

All you have to do now is plug in your values into the above equation and solve for

#q = 150.0 color(red)(cancel(color(black)("g"))) * 0.90"J"/(color(red)(cancel(color(black)("g"))) * color(red)(cancel(color(black)(""^@"C")))) * 127color(red)(cancel(color(black)(""^@"C")))#

#q = "17,145 J"#

Rounded to two **sig figs**, the answer will be

#"amount of heat needed" = color(green)(|bar(ul(color(white)(a/a)color(black)("17,000 J")color(white)(a/a)|)))#