How many mL of a .10 M #NaOH# solution are needed to neutralize 15 mL of .20 M #H_3PO_4# solution? Chemistry Solutions Solutions 1 Answer Michelle Jun 19, 2017 Answer: 30 mL Explanation: Use the formula #M_AV_A = M_BV_B#. #M_A =# Molarity of acid, #V_A =#Volume of acid #M_B =# Molarity of base, #V_B =#Volume of base 1. Plug known values into the formula. #(.20)(15) = .10(x)# 2. Solve for x. #3 = .10x# #x = 30# 30 mL is your answer. Related questions How are solution, solute, and solvent related? Why do solutions become saturated? How does temperature affect solutions? How does a solution differ from a colloid? Calculate the amount of 1 M NaOH aqueous solution needed to make 100 mL of 0.5 M NaOH aqueous ... How does buffering a solution change the solutions behavior? How does Benedict's solution change colour? Describe how would you prepare 1 L of a 1 M solution of sodium chloride. The gram formula weight of ... How do solutions differ from suspensions? How does a solution differ from a compound? See all questions in Solutions Impact of this question 2997 views around the world You can reuse this answer Creative Commons License