# How many molecules are there in 237 grams of "CCl"_4?

$9.28 \cdot {10}^{23}$ molecules of C"Cl_4
Using stoichiometry, we need to convert grams of (C"Cl_4) to moles, then moles to molecules.
237color(red)cancel(color(black)("g")) * (1color(red)cancel(color(black)("mol")))/(153.82color(red)cancel(color(black)("g"))) * (6.02*10^23"molecules")/(1color(red)cancel(color(black)("mol"))) = 9.28 * 10^23" $\text{molecules}$