How many molecules of #NH_3# are produced from #4.82*10^-4# #g# of #H_2#?

1 Answer
Feb 27, 2016

Answer:

#9.58xx10^(19)"molecules"NH_3#

Explanation:

The reaction of making #NH_3# from #H_2# is the following:

#3H_2(g)+N_2(g)->2NH_3(g)#

Therefore, using dimensional analysis, we can use the molar ratio from the balanced equation to find the number of molecules of #NH_3# produced by:

#?"molecules"NH_3=4.82xx10^(-4)cancel(gH_2)xx(1cancel(molH_2))/(2.02cancel(gH_2))xx(2cancel(molNH_3))/(3cancel(molH_2))xx(6.022xx10^(23)"molecules"NH_3)/(1cancel(molNH_3))=9.58xx10^(19)"molecules"NH_3#