# How many moles is 573.28 g of AgCl?

Apr 9, 2016

$4.00 m o l A g C l$

#### Explanation:

Find the relative mass of $A g C l$ by adding together the relative atomic mass of each atom in the compound,

$107.868 g m o {l}^{-} 1 A g + 35.45 g m o {l}^{-} 1 C l = 143.318 g m o {l}^{-} 1 A g C l$

Divide the total mass of how much $A g C l$ by the mass per mole to give you the number of moles,

$\frac{573.28 g}{143.318 g m o {l}^{-} 1} A g C l = 4.00 m o l A g C l$