How many moles of #H_2SO_4# are required to completely neutralize 0.10 moles of #Ca(OH)_2#?

1 Answer
Apr 3, 2017

Answer:

0.10 moles or 9.8 grams.

Explanation:

When the reaction occurs CaSO4 and water (2 molecules) formed.

It means for one mole of sulphuric acid, one mole of Ca(OH)2 reacts.

If you have 0.1 mol of Ca(OH)2, you will need 0.1 mol of sulphuric acid. Or for 7.4 grams Ca(OH)2 you need 9.8 grams (or 0.1 mol) of H2SO4.