# How many moles of MgS_2O_3 are in 235 g of the compound?

A little bit under $2$ $\text{moles}$
$\text{Molar quantity}$ $=$ $\text{Mass"/"Molar mass}$
$=$ $\frac{235 \cdot \cancel{g}}{136.4 \cdot \cancel{g} \cdot m o {l}^{-} 1}$ $=$ ??mol