# How many moles of NaOH are in 10.0 mL of a 3.00 M solution?

May 14, 2016

$M o l a r i t y = \frac{n}{V}$

$n = M \cdot V$

$n = 3.00 M \cdot 10.0 \cdot {10}^{-} 3 L$

n=0.03 mole

#### Explanation:

here in the formula n=# of moles of solute
and V=liter volume of solution