How many moles of oxygen are present in 33.6 L of the gas at 1 atm and 0°C?

1 Answer
Apr 25, 2016

Answer:

#1.5# #mol# #O_2# gas.

Explanation:

We assume that dioxygen gas behaves ideally. Under the given conditions, an ideal gas has a volume of #22.4*L*mol^-1#.

So we simply divide the volume by the molar volume under standard conditions, #22.4*L*mol^-1#.

#(33.6*cancelL)/(22.4*cancelL*mol^-1)# #=# #?? mol#

How did I know that the molar volume of an ideal gas at #"STP"# was #22.4*L#? You would be given this information as supplementary material in any examination.