# How many moles of oxygen are present in 33.6 L of the gas at 1 atm and 0°C?

Apr 25, 2016

$1.5$ $m o l$ ${O}_{2}$ gas.

#### Explanation:

We assume that dioxygen gas behaves ideally. Under the given conditions, an ideal gas has a volume of $22.4 \cdot L \cdot m o {l}^{-} 1$.

So we simply divide the volume by the molar volume under standard conditions, $22.4 \cdot L \cdot m o {l}^{-} 1$.

$\frac{33.6 \cdot \cancel{L}}{22.4 \cdot \cancel{L} \cdot m o {l}^{-} 1}$ $=$ ?? mol

How did I know that the molar volume of an ideal gas at $\text{STP}$ was $22.4 \cdot L$? You would be given this information as supplementary material in any examination.