How many moles of sodium carbonate contain #1.773 xx 10^17# carbon atoms?
1 Answer
Nov 12, 2016
If we want
#"1 mol C" = "1 mol Na"_2"CO"_3#
Therefore:
#color(blue)(1.773xx10^17 "C atoms") xx ("1 mol C")/(6.022xx10^23 "C atoms") xx ("1 mol Na"_2"CO"_3)/("1 mol C")#
#= color(blue)(2.944xx10^(-7) "mols Na"_2"CO"_3)#