How many moles of water are there in 1.538 L?

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Answer 1 · 2016-09-08T07:46:35

Approx. #85*mol#

#"Moles of substance"#

#=# #("Mass of substance "*g)/("Molecular mass of substance "*g*mol^-1#

I get an answer in #mol#.

Thus for #1.538*L#, we get,

#(1.528*cancelLxx1000*cancel(mL)*cancelL^-1xx1.00*cancelg*cancel(mL^-1))/(18.01*cancelg*mol^-1)#

#=# #??mol#

The density of water #=# #1*g*mL^-1#.