# How many moles of water are there in 1.538 L?

Sep 8, 2016

Approx. $85 \cdot m o l$

#### Explanation:

$\text{Moles of substance}$

$=$ ("Mass of substance "*g)/("Molecular mass of substance "*g*mol^-1

I get an answer in $m o l$.

Thus for $1.538 \cdot L$, we get,

$\frac{1.528 \cdot \cancel{L} \times 1000 \cdot \cancel{m L} \cdot {\cancel{L}}^{-} 1 \times 1.00 \cdot \cancel{g} \cdot \cancel{m {L}^{-} 1}}{18.01 \cdot \cancel{g} \cdot m o {l}^{-} 1}$

$=$ ??mol

The density of water $=$ $1 \cdot g \cdot m {L}^{-} 1$.