How many Oxygen atoms in 1.44 x 10^5 kg of Nitrogen Oxide?

1 Answer
Jul 17, 2017

Answer:

Well, I will do it for #NO_2(g)#........and get over six million moles......

Explanation:

But of course there is #NO# and #N_2O#.........

For #NO_2#, we have a molecular mass of #46.01*g*mol^-1#.

And thus #"Moles of"# #NO_2# #=# #(1.44xx10^8*g)/(46.01*g*mol^-1)#

#-=3.13xx10^6*mol#....and thus #6.26xx10^6*mol# #"oxygen atoms."#

Then, you continue to solve for the number of oxygen atoms.

#6.26xx10^6*molxx6.022 * 10^23*mol^-1~= 4.0xx10^30# #"oxygen atoms"# which is nearer to the given answer.