How many triple bonds are present in the compound #C_2H_2#?

1 Answer
Nov 3, 2015

One.

Explanation:

Your best strategy when dealing with such questions is to draw the Lewis structure of the molecule.

So, acetylene, #"C"_2"H"_2#, has a total of #10# valence electrons - #4# from each of the two carbon atoms and #1# from each of the two hydrogen atoms.

Now, when you draw a Lewis structure, you need to make sure that the atoms that are a part of the molecule have a complete octet.

SInce the hydrogen atoms can only form one bond, you know for a fact that will each be bonded to a carbon atom. This will account for #4# of the #10# valence electrons, #2# for each hydrogen - carbon single bond.

This means that the two carbo natoms must be bonded to each other. In order for them to have completel octets, you need to form a triple bond, which will use up the remaining #6# valence electrons, between them.

The Lewis structure will thus look like this

https://www.studyblue.com/notes/note/n/orch-234-study-guide-2012-13-kelley/deck/9724320

So, now you're redy to answer the question - each acetylene molecule has one triple bond. This triple bond consists of one sigma bond and two pi bonds.

http://www.nyu.edu/classes/tuckerman/adv.chem/lectures/lecture_17/node5.html