How many vertical asymptotes does the graph of #f(x)=3/(5(x+9))#?
1 Answer
Sep 28, 2016
one at x = -9
Explanation:
The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non-zero for this value then it is a vertical asymptote.
solve:
#5(x+9)=0rArrx=-9" is the asymptote"#
graph{(3)/(5(x+9)) [-10, 10, -5, 5]}