How much energy can be stored in a spring with #k=450# # N##/m# if the maximum possible stretch is #18# #cm#?

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Answer 1 · 2018-01-02T13:37:57

The energy stored is #=7.29J#

The energy stored in a spring is

#E=1/2kx^2#

The spring constant is #k=450Nm^-1#

The stretch is #x=0.18m#

Therefore,

The energy stored is

#E=1/2*450*0.18^2=7.29J#