How much greater is #(-13x^2 - 13x - 10) + (19x^2 - 19x - 5)#?

1 Answer
Jun 19, 2015

Answer 1: #=color(red)(-32x^2 + 6x-5#
Answer 2:#= color(red)(6x^2) color(blue)(-32x) -15#

Explanation:

There are two ways of interpreting this question

  1. How much greater is #-13x^2 - 13x - 10 # than #19x^2 - 19x -5#

Here we need to subtract:
#-13x^2 - 13x - 10 #
#color(red)(-)19x^2 color(red)(+) 19x color(red)(+)5#
#=color(red)(-32x^2 + 6x-5#

2.The second way is by adding the two as addition #color(green)(+# has been mentioned in the question.

#-13x^2 - 13x - 10 + 19x^2 - 19x -5#

grouping like terms
#= color(red)((-13 x^2 + 19x^2)) + color(blue)((-13x - 19x)) + (-10 - 5)#
#= color(red)(6x^2) color(blue)(-32x) -15#