# How much greater is (-13x^2 - 5x - 14) + (-14x^2 - 20x + 8)?

Jun 19, 2015

answer 1: =color(red)(x^2 + 15x -22
answer 2: = color(red)(-27x^2-25x -6

#### Explanation:

There are two ways of interpreting this question

1. How much greater is $- 13 {x}^{2} - 5 x - 14$ than $- 14 {x}^{2} - 20 x + 8$

Here we need to subtract:
$- 13 {x}^{2} - 5 x - 14$
$\textcolor{red}{+} 14 {x}^{2} \textcolor{red}{+} 20 x \textcolor{red}{-} 8$
=color(red)(x^2 + 15x -22

2.The second way is by adding the two as addition color(green)(+ has been mentioned in the question.

$- 13 {x}^{2} - 5 x - 14 - 14 {x}^{2} - 20 x + 8$
grouping like terms
$= \textcolor{red}{\left(- 13 {x}^{2} - 14 {x}^{2}\right)} + \textcolor{b l u e}{\left(- 5 x - 20 x\right)} + \left(- 14 + 8\right)$
$= \textcolor{red}{- 27 {x}^{2}} \textcolor{b l u e}{- 25 x} - 6$