# How much greater is (17x^2 + 20x + 11) + (15x^2 + 11x + 17)?

Jun 19, 2015

answer 1:  = color(red)(2x^2 + 9x -6
answer 2: $= \textcolor{red}{32 {x}^{2}} + \textcolor{b l u e}{31 x} + 28$

#### Explanation:

There are two ways of interpreting this question:

• How much greater is $\left(17 {x}^{2} + 20 x + 11\right)$than $\left(15 {x}^{2} + 11 x + 17\right)$

Here we need to subtract:
$17 {x}^{2} + 20 x + 11$
$\textcolor{red}{-} 15 {x}^{2} \textcolor{red}{-} 11 x \textcolor{red}{-} 17$
 = color(red)(2x^2 + 9x -6

• The second way of interpreting is by adding as the addition sign $+$ has been used in the question

Grouping like terms:
$= \textcolor{red}{\left(17 {x}^{2} + 15 {x}^{2}\right)} + \textcolor{b l u e}{\left(20 x + 11 x\right)} + \left(17 + 11\right)$
$= \textcolor{red}{32 {x}^{2}} + \textcolor{b l u e}{31 x} + 28$