How much greater is (-20x^2 + 13x - 4) than (11x^2 - 13x - 10)?

May 16, 2018

$= - 31 {x}^{2} + 26 x + 6$

Explanation:

Consider the question. How much is $20$ greater than 16?

We would do $20 - 16 = 4$

In the same way.....

How much greater is $\left(- 20 {x}^{2} + 13 x - 4\right)$ than $\left(11 {x}^{2} - 13 x - 10\right)$ will be done as a subtraction.

$\rightarrow \left(- 20 {x}^{2} + 13 x - 4\right) - \left(11 {x}^{2} - 13 x - 10\right)$

$= - 20 {x}^{2} + 13 x - 4 - 11 {x}^{2} + 13 x + 10 \text{ } \leftarrow$ notice the signs

$= - 31 {x}^{2} + 26 x + 6$