Question

How much heat energy is required to convert 2kg of ice at 0°C to water at the same temperature? Latent heat of fusion of water= 3.3X10^5

Answer 1

`6.6xx10^5` `J`

Explanation:

We should know that, the temperature remains constant during the change of phase of matter (solid to liquid) even if we apply heat. This that we supply to facilitate the change of phase is known as Latent heat.

To solve this question, we need to know the formula

`color(blue)(Q=mL_f`

Where, `Q`is the heat energy required. `m` is the mass and #L _f# is the latent heat of fusion

We know, that the mass is `color(brown)(2` `color(brown)(kg` ant he Latent heat of fusion of ice is `color(red)(3.3*10^5` `color(red)(J/(kg)`

So,

`rarrQ=2` `cancel(kg)*3.3*10^5` `J/cancel(kg)`

`rarr3.3*2*10^5` `J`

`color(green)(rArr6.6*10^5` `color(green)("Joules"`

Hope that helps