# How much heat energy (Joules) is required to raise the temperature of 120.0 g of wate from -90 C to -5 C?

Sep 4, 2017

Approximately $4.5 \cdot {10}^{4} J$ of energy, this isn't surprising because water has an unusually high ability to absorb heat.

#### Explanation:

This specific heat value is needed to solve your question; it should be contained within any table of thermochemical data (e.g. look in your text).

C_s = (4.184J)/(g*°C)

$q = m {C}_{s} \Delta T$

The above equation relates these variables to arrive at the energy required to raise the substance's temperature to the desired temperature in your case.

q = 120.0g * (4.184J)/(g*°C) * 90°C
$\therefore q \approx 4.5 \cdot {10}^{4} J$