How much heat energy (Joules) is required to to raise the temperature of 120.0 g of water from -90 C to -5 C?

1 Answer
Apr 24, 2018

Answer:

#"21.5 kJ"#

Explanation:

Use this equation

#"Q = mC"Δ"T"#

where

  • #"Q ="# Heat
  • #"m ="# Mass of sample
  • #"C ="# Specific heat of sample (#"2.108 J/g°C"# for ice)
  • #"ΔT ="# Change in temperature

#"Q" = 120 cancel"g" × "2.108 J"/(cancel"g" cancel"°C") × [-5 - (-90)] cancel"°C" = "21501.6 J" ≈ "21.5 kJ"#