# How much heat (in kJ) is released when 1.65 mol NaOH(s) is dissolved in water? The molar heat of solution of NaoH is -445.1 kJ/mol.

Jun 11, 2017

We are given that............and get $\Delta {H}_{\text{rxn}} = - 734.4 \cdot k J$

#### Explanation:

We are given that......

$N a O H \left(s\right) \stackrel{{H}_{2} O}{\rightarrow} N {a}^{+} + H {O}^{-} + \Delta$

Where $\Delta = 445.1 \cdot k J$ per mole of reaction as written........the enthalpy term was NEGATIVE and thus we regard heat as a product.

And this in your proposed reaction:

${\Delta}_{\text{rxn}} = 1.65 \cdot m o l \times \left(- 445.1 \cdot k J \cdot m o {l}^{-} 1\right) = - 734.4 \cdot k J$