Question

How much heat (in kJ) is released when 1.65 mol NaOH(s) is dissolved in water? The molar heat of solution of NaoH is -445.1 kJ/mol.

Answer 1

We are given that............and get `DeltaH_"rxn"=-734.4*kJ`

Explanation:

We are given that......

`NaOH(s) stackrel(H_2O)rarrNa^(+) + HO^(-) + Delta`

Where `Delta=445.1*kJ` per mole of reaction as written........the enthalpy term was NEGATIVE and thus we regard heat as a product.

And this in your proposed reaction:

`Delta_"rxn"=1.65*molxx(-445.1*kJ*mol^-1)=-734.4*kJ`