# How much heat is added when 22 grams of water are heated from 10°C to 15°C?

Jul 4, 2016

And the heat capacity of water is ?? $J \cdot {K}^{-} 1 \cdot {g}^{-} 1$?

#### Explanation:

We have $\text{mass}$, we have $\Delta T$. We don't have no heat capacity of water.

SO I will take pity on you. The specific heat capacity of water is $4.184 \cdot J \cdot {K}^{-} 1 \cdot {g}^{-} 1$. As specific heats go, this is very large.

And thus $\Delta H$ $=$ $\text{Mass "xx" Specific heat "xx} \Delta T$

$=$ 22*gxx4.184*J*(""^@C)^-1*g^-1xx5""^@C $\cong 500 \cdot J$

I am free to interchange $\text{degrees Kelvin}$ and $\text{degrees Celsius}$ because $\Delta T$ is specified.