How much heat is added when 22 grams of water are heated from 10°C to 15°C?

1 Answer
anor277
Jul 4, 2016

And the heat capacity of water is ?? J*K^-1*g^-1?

Explanation:

We have "mass", we have DeltaT. We don't have no [heat capacity of water.](http://water.usgs.gov/edu/heat-capacity.html)

SO I will take pity on you. The specific heat capacity of water is 4.184*J*K^-1*g^-1. As specific heats go, this is very large.

And thus DeltaH = "Mass "xx" Specific heat "xx""DeltaT

= 22*gxx4.184*J*(""^@C)^-1*g^-1xx5""^@C ~=500*J

I am free to interchange "degrees Kelvin" and "degrees Celsius" because DeltaT is specified.

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