How much heat is given off when 1.25 grams of silver is cooled from 100.0 C to 80.0 C?

Question

The specific heat of silver is O.057 cal/g C

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Answer 1 · 2017-12-24T16:32:39

The heat is $=$ $"1.43 cal"$ .

Use

$q = m xx s xx Delta T$

Here the mass, $m$ , is $"1.25 g"$ , the specific heat, $s$ , is $"0.057 cal g"^(-1) ""^@"C"^(-1)$ , and

$Delta T = |80.0^@"C" - 100^@"C"| = 20^@"C"$

So

$"Heat liberated" = 1.25 xx 0.057 xx 20 = "1.43 cal"$