# How much heat is needed to raise the temperature of 5.58 kilograms of iron from 20.0°C to 1000.0°C?

## The specific heat of iron is 450,000 J(kg * °C).

Feb 27, 2016

$2.46 \times {10}^{9} J$

#### Explanation:

Given:
$m a s s \left(m\right) = 5.58 k g$
$\Delta T$=(T_2-T_1)=$\left({1000}^{o} C - {20}^{o} C\right) = {980}^{o} C$
$C p = \frac{450 , 000 J}{k g {.}^{o} C}$

Required:
Heat (Q)= ? J

Solution:

From the Formula:

$Q = m C p \Delta T$
$Q = 5.58 \cancel{k g}$ $\times$ (450,000J)/(cancel(kg.^oC) $\times$ $980.0 \cancel{^ o C}$
$Q = 2.46$ $\times$ ${10}^{9} J$