How much heat is needed to raise the temperature of 5.58 kilograms of iron from 20.0°C to 1000.0°C?

Question

The specific heat of iron is 450,000 J(kg * °C).

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Answer 1 · 2016-02-27T12:22:08

#2.46xx 10^9 J#

Given:
#mass(m)=5.58kg#
#DeltaT#=#(T_2#-#T_1)#=#(1000^oC-20^oC)=980^oC#
#Cp= (450,000 J)/(kg.^oC)#

Required:
#Heat (Q)= ? J#

Solution:

From the Formula:

#Q=mCpDeltaT#
#Q=5.58cancel(kg)# # xx# #(450,000J)/(cancel(kg.^oC)# #xx# #980.0cancel(^oC)#
#Q=2.46# #xx# #10^9J#