How much heat is released when 88.2 g of water cools from 33.8°C to 12.9°C?

1 Answer
anor277
Jun 22, 2016

The specific heat of water is 4.186*J*g^-1*K^-14.186⋅J⋅g−1⋅K−1. This should have been quoted with the question.

Explanation:

The specific heat of water is high as specific heats go. Part of the reason is that water is a very dense substance.

Heat transferred == DeltaTxxC_Pxx"mass

= -20.9*Kxx88.2*gxx4.186*J*g^-1*K^-1

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