Question

How much heat is required to melt 185 grams of ice at 0-degree Celsius and then raise the temperature of the resulting water to 32.0 degrees Celsius?

Answer 1

Q= 86571J

Explanation:

To melt ice you need:
`Q_1= m xx lambda_m = 185 g xx 334 J/g= 61790 J`
To rice the temperature from 0 to 32 °C you need:
`Q_2= m xx cp xx Delta T= 185 g xx 4,186 J/(g °C) xx 32°C= 24781 J`
`Q_t=Q_1 + Q_2 =61790 J+24781 J= 86571J`