How much heat is required to raise the temperature of a 50.0 g block of iron by 10.0^@"C"10.0C ? Specific heat of iron: "0.449 J/g"""^@"C"0.449 J/gC

1 Answer
Sep 15, 2016

"225 J"225 J

Explanation:

The key to this problem is the specific heat of iron, which is said to be equal to

c_"iron" = "0.449 J g"^(-1)""^@"C"^(-1)ciron=0.449 J g1C1

As you know, the specific heat of a substance tells you how much heat is needed to raise the temperature of a sample of "1 g"1 g by 1^@"C"1C.

Keep in mind that this represents the amount of heat needed per gram, per degree Celsius!

So, how much heat would be needed to increase the temperature of a "50.0 g"50.0 g block of iron by 1^@"C"1C ?

50.0 color(red)(cancel(color(black)("g"))) * overbrace("0.449 J" /(1color(red)(cancel(color(black)("g"))) ""^@"C"))^(color(blue)("the specific heat of iron")) = "22.45 J" ""^@"C"^(-1)

This means that in order to increase the temperature of "50.0 g" of iron by 1^@"C" you need to provide it with "22.45 J" of heat.

You can thus say that in order to increase the temperature of the block by 10.0^@"C", you must provide ten times as much heat

10.0 color(red)(cancel(color(black)(""^@"C"))) * overbrace("22.45 J"/(1color(red)(cancel(color(black)(""^@"C")))))^(color(blue)("for 50.0 g of iron")) = color(green)(bar(ul(|color(white)(a/a)color(black)("225 J")color(white)(a/a)|)))

The answer is rounded to three sig figs.