# How much heat is required to raise the temperature of a 50.0 g block of iron by #10.0^@"C"# ? Specific heat of iron: #"0.449 J/g"""^@"C"#

##### 1 Answer

#### Explanation:

The key to this problem is the specific heat of iron, which is said to be equal to

#c_"iron" = "0.449 J g"^(-1)""^@"C"^(-1)#

As you know, the **specific heat** of a substance tells you how much heat is needed to raise the temperature of a sample of

Keep in mind that this represents the amount of heat needed **per gram**, **per degree Celsius**!

So, how much heat would be needed to increase the temperature of a

#50.0 color(red)(cancel(color(black)("g"))) * overbrace("0.449 J" /(1color(red)(cancel(color(black)("g"))) ""^@"C"))^(color(blue)("the specific heat of iron")) = "22.45 J" ""^@"C"^(-1)#

This means that in order to increase the temperature of

You can thus say that in order to increase the temperature of the block by **ten times** as much heat

#10.0 color(red)(cancel(color(black)(""^@"C"))) * overbrace("22.45 J"/(1color(red)(cancel(color(black)(""^@"C")))))^(color(blue)("for 50.0 g of iron")) = color(green)(bar(ul(|color(white)(a/a)color(black)("225 J")color(white)(a/a)|)))#

The answer is rounded to three **sig figs**.