How much power is produced if a voltage of 6 V is applied to a circuit with a resistance of 60 Omega?

Feb 22, 2016

Power $= 600 m W$

Explanation:

Things you need to know:

$P = I V$ (Power equals current times voltage)

$I = \frac{V}{R}$ (Current equals voltage divided by resistance

1" Ampere" = (1 " Volt")/(1 "Ohm")

$1 \text{ Watt" = 1 " Ampere" * 1" Volt}$

$1 \text{ miliWatt (mW)" = 1" Watt}$

Application

I= (6" V")/(60 Omega) = 0.1 " A"

$P = 0.1 \text{ A"xx6" V"= 0.6 " W" = 600" mW}$